Python 统计文件夹大小：找出最占空间的文件
import os
def folder_size(path):
total = 0
for root, _, files in os.walk(path):
for name in files:
try:
total += os.path.getsize(os.path.join(root, name))
except OSError:
pass
return total
def human(n):
for unit in ['B', 'KB', 'MB', 'GB', 'TB']:
if n < 1024:
return f"{n:.2f} {unit}"
n /= 1024
def top_files(folder, top=20):
items = []
for root, _, files in os.walk(folder):
for name in files:
path = os.path.join(root, name)
try:
items.append((os.path.getsize(path), path))
except OSError:
pass
items.sort(reverse=True)
for size, path in items[:top]:
print(f"{human(size):>10} {path}")
top_files('D:/', top=20)
更新时间：2026-09-14 13:42:32